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Let `omega != 1` be a complex cube root of unity. If `(4+5 omega+6omega^2)^(n^2+2)+(6+5omega^2+4omega)^(n^2+2)+(5+6omega+4omega^2)^(n^2+2)=0` then n can be- - Sarthaks eConnect
Let `omega != 1` be a complex cube root of unity. If `(4+5 omega+6omega^2)^(n^2+2)+(6+5omega^2+4omega)^(n^2+2)+(5+6omega+4omega^2)^(n^2+2)=0` then n can be-
