Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) The circumference of the circle `x^2+y^2-2x+8y-q=0` is bisected by the circle `x^2+y^2+4x+12y+p=0`, then p+q is equal to - Sarthaks eConnect
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The circumference of the circle `x^2+y^2-2x+8y-q=0` is bisected by the circle `x^2+y^2+4x+12y+p=0`, then p+q is equal to

The circumference of the circle `x^2+y^2-2x+8y-q=0` is bisected by the circle `x^2+y^2+4x+12y+p=0`, then p+q is equal to

A.

25

B.

100

C.

10
D.

48

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