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A function y=f(x) satisfies the differential equation `f(x). sin2x-cos x+(1+sin^2 x) f(x)=0` where f(0)=0. Then value of `f(pi/6)` is equal to
A. |
`1/5` |
B. |
`3/5` |
C. |
`4/5` |
D. |
`2/5` |
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