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Given three points P, Q, R with P(5,3) and R lies on the x-axis. If equation of RQ is x-2y=2 and PQ is parallel to the x-axis, then the centroid of `triangle PQR` lies on the line
A. |
x-2y+1=0 |
B. |
2x+y-9=0 |
C. |
2x-5y=0 |
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D. |
5x-2y=0 |