Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) A protonmoves on circular path with its constant angular speed then correct relation between its magnetic moment and angular momentum - Sarthaks eConnect
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Practice Online Test Series for JEE Main 2018 & NEET 2018

A proton  moves on circular path with its constant angular speed then correct relation between its magnetic moment and angular momentum:

A.

`vecM=(-evecL)/(2m_p)`

B.

`vecM=(evecL)/(2m_p)`

C.

`vecM=((2e)/(m_p))vecL`

D.

`vecM=-((2e)/(m_p))vecL`