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Consider the function `f(x) =8x^2 -7x+ 5` on the interval `[-6,6]` . The value of c that satisfies the condition of the Lagrange's mean value theorem, is
A. |
`-7/8` |
B. |
-4 |
C. |
`7/8` |
D. |
0 |
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`f'(c)=16c-7=(f(6)-f(-6))/12=((8.36-7.6+5)-(8.36+7.6+5))/12=-(2xx7xx6)/12=-7`
`16c=0=>c=0.`