Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) lf coefficient of friction between all surfaces is 0.4. then the minimum horizontal force F to have the equilibrium of the system will be. (g = 10m / `s^2`) - Sarthaks eConnect

lf coefficient of friction between all surfaces is 0.4. then the minimum horizontal force F to have the equilibrium of the system will be. (g = 10m / `s^2`)

lf coefficient of friction between all surfaces is 0.4. then the minimum horizontal force F to have the equilibrium of the system will be. (g = 10m / `s^2`)

A.

62.5 N

B.

150 N

C.

135 N

D.

50 N

Solution

0 votes

Best answer

From horizontal equilibrium of blocks `N_1=N_2=F` hence limiting frictions are `f_(I_1)=f_(I_2)=mu F` equations are