Consider the following reaction
`(i) S(s)+O_2(g)->SO_2(g); triangleH=-297` KJ/mol
`(ii) S(s)+3/2O_2(g)->SO_3(g); triangleH=-396` KJ/ mol
`(iii) O_2(g)->20(g); triangleH=-495` KJ /mol
How would the reaction energies be added to get the reaction giving the S—O bond energy in `SO_3`
| A. |
`(i)–(ii) + 1/2(iii)` |
 |
| B. |
`(i) + (ii) + 1/2 (iii)` |
| C. |
`(i), (ii), (iii)` |
| D. |
`(i)–(ii) + 3/2 (iii)` |
Reaction `SO_3(g)->SO_2(g)+O(g)`
given the S—O bond energy
This equation is obtained by dividing, Eq. (iii) by 2 and then addition with Eq. (i). Now Eq. (ii) is ubstracted from teh equation obtained
, i.e., Eq. (i) – Eq. (ii) + `1/2` Eq.(iii).