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The number of stereoisomers of compound `CH_3 -CH = CH-CH(Br)CH_3` are:
A. |
2 |
B. |
3 |
C. |
4 |
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D. |
6 |
`CH_3 - CH = CH - CH(Br) - CH_3` has 4 stereoisomers, with (2Z,4R), (2Z,4S), (2E,, 4S) configurations.