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If the lines `x+ay=a, bx+y=b` and `cx+cy=1` are concurrent, then the value of `a/(1-a)+b/(1-b)+c/(1-c)` is:
A. |
0 |
B. |
1 |
C. |
-1 |
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D. |
none of these |
`1{(1-b)(1-c)}-b{(a-1)(1-c)}+c{-(a-1)(1-b)}=0`