Equation of plane meeting co-ordinate axes at A, B and C if (a, b, c) is centroid of `triangle ABC` is:
| A. |
`x/a+y/b+z/c=1` |
| B. |
`x/a+y/b+z/c=1/3` |
| C. |
`x/a+y/b+z/c=3` |
 |
| D. |
None of these |
Let equation of plane is `x/alpha+y/beta+z/gamma=1`, then `A(alpha,0,0),B(0,beta,0)` and `C(0,0,gamma).` Now `alpha/3=a,beta/3=b` and `gamma/3=c` [as (a,b,c) is centroid of given triangle ] so put `alpha=3a,beta=3b` and `gamma=3c` is equation of plane .
Equation of plane `=> x/a+y/b+z/c=3`