Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) A spherical surface of radius of curvature R, separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O and PO =OQ. The distance PO is equal to - Sarthaks eConnect

A spherical surface of radius of curvature R, separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O and PO =OQ. The distance PO is equal to

A spherical surface of radius of curvature R, separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O and PO =OQ. The distance PO is equal to

A.

5 R

B.

3 R

C.

2 R

D.

1.5 R

Solution

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Best answer

(Distance are measured from O and are taken as positive in the direction of ray of light)

so, `2.5/X=0.5/R`

`=>X=5R`