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Practice Online Test Series for JEE Main 2018 & NEET 2018
Solution of `(x^2-2x^3y^3)dy=(3x^2y^4+2xy) dx` is
`x^2/y=c(x+y)`
`x^2/y+x^3y^2=C`
`x^2/y+xy=C`
`x^2/y=C(x+1)`