Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) Total no. of triplets `(alpha, beta, gamma)` satisfying `cos(alpha-beta)+ cos(beta-gamma)+cos(gamma-alpha)=3` and `cos(alpha+beta)=cos(beta+gamma)= cos(gamma+alpha)=1/sqrtpi, (0<=alpha, beta, gamma <=2pi)` - Sarthaks eConnect

Total no. of triplets `(alpha, beta, gamma)` satisfying `cos(alpha-beta)+ cos(beta-gamma)+cos(gamma-alpha)=3` and `cos(alpha+beta)=cos(beta+gamma)= cos(gamma+alpha)=1/sqrtpi, (0<=alpha, beta, gamma <=2pi)`

Total no. of triplets `(alpha, beta, gamma)` satisfying `cos(alpha-beta)+ cos(beta-gamma)+cos(gamma-alpha)=3` and `cos(alpha+beta)=cos(beta+gamma)= cos(gamma+alpha)=1/sqrtpi, (0<=alpha, beta, gamma <=2pi)`

A.

2

B.

4

C.

6

D.

7

Solution

0 votes

Best answer

This is possible when

`alpha=beta=gamma`

`=> cos 2alpha=1/sqrtx=>` There exist four values of alpha , so there are possible triplets.