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Excess of KI reacts with `CuSO_4` solution and then `Na_2S_2O_3` solution is added to it. Which of the following statements is incorrect for this reaction?
A. |
Evolved `I_2` is reduced |
B. |
`CuI_2` is formed |
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C. |
`Na_2S_2O_3` is oxidised |
D. |
`Cu_2I_2` is formed |
`2CuSO_4+KI2K_2SO_4+Cu_2I_2+I_2`
`2Na_2S_2O_3+I_2Na_2S_4O_6+2NaI ; CuI_2` is not formed according to following reaction.
`2CuI_2`(unstable) `Cu_2I_2+I_2`