Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) An ideal gas is initially at temperature T and volume v. Its volume is increased by `Delta V` due to an increase in temperature `Delta T`, pressure remaining constant. The quantity `delta= (Delta V)/( V Delta T)` varies with temperature as - Sarthaks eConnect

An ideal gas is initially at temperature T and volume v. Its volume is increased by `Delta V` due to an increase in temperature `Delta T`, pressure remaining constant. The quantity `delta= (Delta V)/( V Delta T)` varies with temperature as

An ideal gas is initially at temperature T and volume v. Its volume is increased by `Delta V` due to an increase in temperature `Delta T`, pressure remaining constant. The quantity `delta= (Delta V)/( V Delta T)` varies with temperature as

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D.

Solution

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Therefore, `delta` is inversely proportional to temperature T. i.e., when T increases, `delta` decreases and viceversa.
Hence, `delta -T` graph will be a rectangular hyperbola as shown in the above figure.