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The ionization isomer of `[Cr(H_2O)_4Cl(NO_2)]Cl` is:

A.

`[Cr(H_2O)_4(O_2N)]Cl_2`

B.

`[Cr(H_2O)_4Cl_2](NO_2)`

C.

`[Cr(H_2O)_4Cl(ONO)]Cl`

D.

`[Cr(H_2O)_4Cl_2(NO_2)].H_2O`

Solution

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Gives different ions in the solution