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If A + B + 1, then in terms of Boolean algebra the value of A.B + A is not equal to
A. |
B.A+B |
B. |
B+A |
C. |
B |
D. |
`barA.B` |
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If A=B=1; then A.B+A=1.1+1=1 then `barA.B=bar1 .1=0.1=0`