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The term independent of x in the expansion of `(9x-1/(3sqrtx))^18`, x > 0, is `alpha` time the corresponding binomial coefficient. Then `alpha` is :
A. |
3 |
B. |
`1/3` |
C. |
`-1/3` |
D. |
1 |
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`T_(r+1)=18C_rxx(9x)^(18-r)xx(-1)^rxx((x)^(-r/2))/3^r`
`T_(r+1)=18C_rxx9^(18-r)xx(-1)^2/3^rxx x^18-(3r)/2`
`18-(3r)/2=0`
`r=12`
`18C_12xx9^6/3^12=alphaxx18C_12`
`alpha=1`