Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) Let i= `sqrt(-1)`. Define a sequence of complex number by `z_1=0 , z_(n+1)=z_n^2+1` for n `>=` 1. In the complex plane, then arg(`z_(111)`) is - Sarthaks eConnect
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Let i= `sqrt(-1)`. Define a sequence of complex number by `z_1=0 , z_(n+1)=z_n^2+1` for n `>=` 1. In the complex plane, then arg(`z_(111)`) is :

A.

`pi/4`

B.

`-pi/4`

C.

`(3pi)/4`

D.

`pi/2`

Solution

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Best answer

`z_1 = 0, z_(n+1)= z_n^2+i`

Put n = `1 =>z_2=z_1^2+i=i`

Put n=`2 =>z_3 =z_2^2+i= i^2 + i = i – 1`

Put n = `3=>z_4 = z_3^2+i = (i–1)^2+ i = –i`

Put n =` 4 =>z_5=z_4^2+ i = (–i)^2 + i = i –1`

Put n = `5 =>z_6 = z_6 ^2 + i = (i–1)^2 + i = – i`

Thus arg`(z_(111))` = arg(i-1) = `(3pi)/4`