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The number of points of discontinuity for the function ƒ(x) = (log|x|)sgn`(x^2–1)`, x `!=` 0, is/are :
A. |
1 |
B. |
2 |
C. |
0 |
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D. |
none of these |
Sgn`(x^2 – 1)` is discontinuous when`x^2` – = 0
or x = ± 1
But log |x| = 0 when x = ± 1 Hence, ƒ(x) = is continuous at x = ±1
Thus, ƒ(x) is always continuous