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If ƒ(x) is continuous and `int_0^9 f(x)dx=4` then value of the integral `int_0^3x xx f(x^2)dx` is
A. |
2 |
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B. |
18 |
C. |
16 |
D. |
4 |
Let I=`int_0^3x xx f(x^2)dx ; put x^2=t and 2x xx dx =dt`
Now I =`1/2 int_0^9f(t)dt=1/2xx4=2`