Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) P and Q are points on the ellipse `x^2/a^2+y^2/b^2=1` whose centre is C. The accentric angles of P and Q differe by a right angle. If `/_PCQ` is maximum, then eccentric angle of P can be - Sarthaks eConnect
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P and Q are points on the ellipse `x^2/a^2+y^2/b^2=1` whose centre is C. The accentric angles of P and Q differe by a right angle. If `/_PCQ` is maximum, then eccentric angle of P can be :

A.

`pi/6`

B.

`pi/4`

C.

`pi/3`

D.

`pi/12`

Solution

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Since the eccentric of P and Q differ by a right ange, we can take P as `(a costheta, bsintheta)` and Q as `(–a sintheta,bcostheta)`. Slope of CP =`(bsintheta)/(acostheta)`

Slope of CQ =` – (bcostheta)/(asintheta)`

If Q is the angle between CP and CQ, then



Q is minimum, if sin `2theta` is maximum

i.e, if `2theta=pi/2`

or `theta=pi/4`