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The function ƒ : `[a, oo) -> R` where R denotes the range corresponding to the given domain, with rule ƒ(x) =` 2x^3 – 3x^2 + 6,` will have an inverse provided
A. |
`a<=1` |
B. |
`a>=0` |
C. |
`a<=0` |
D. |
`a>=1` |
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`ƒ(x) = 2x^3 –3x^2 + 6`
`ƒ'(x) = 6x^2 – 6x = 6(x^2 – x)`
`ƒ'(x) = 0 => 6(x^2 – x) = 0 `
`=>x = 0 or x = 1`
For inverse to exist, functon must be one-one onto. Hence, the domain is [1, `oo`) Hence, a `>=`1.