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A box contains 4 white and 3 black balls. Another box contains 3 white and 4 black balls. A die is thrown. If it exhibits a number `<=`3, the ball is drawn from the first box. Otherwise, a ball is drawn from the second box. A ball drawn is found to be black. The probability that it has been drawn from the second box is :
A. |
`3/7` |
B. |
`4/7` |
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C. |
`6/17` |
D. |
`8/17` |
`E_1 ->` event of drawing a ball from first box
`E_2->` Drawing a ball from `2^(nd)` box
`P(E_2/B)=(P(E_2nnnB))/(P(B))`
`=(P(E_2) P(B/E_2))/(P(E_1).P(B/E_1)+P(E_2).P(B/E_2))`
`=((1/2).(4/7))/((1/2).(3/7)+(1/2).(4/7))`
`=4/7`