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If `a_1, a_2, a_3`..... is an arithmetic progression with common difference 1 and `a_1 + a_2 + a_3 + ....+ a_98` = 137 the value of `a_2 + a_4 + a_6 +..... + a_98` is :
A. |
95 |
B. |
91 |
C. |
93 |
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D. |
97 |
d=1 let `a_1=a`
`a_1+a_2+.............+a_98=137`
`98/2[2a+97]=137` .............(1)
49(2a+97)=137
`2a+97=137/49` .................(2)