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If `m_1, m_2` are the roots of the equation `x^2+(sqrt3+2)x+sqrt3-1=0`then the area of the triangle formed by the lines y = `m_1x, y = m_2x` and y=2 is :
A. |
`sqrt33-sqrt11` sq. unit |
B. |
`sqrt11+sqrt33` sq. unit |
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C. |
`2sqrt33` sq. unit |
D. |
121 sq. unit |
Vertices of the triangle are `(0, 0),(2/m_1,2)(2/m_2,2)`