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In an fcc arrangement of A and B atoms, where A atoms are at the corners of the unit cell, B atoms at the face centres, two atoms are missing from two corners in each unit cell, then the simplest formula of the compound is :
A. |
`A_7B_6` |
B. |
`A_6B_7` |
C. |
`A_7B_24` |
D. |
`AB_4` |
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Since there are six atoms (A) in the corner of th unit cell, the contribution of atoms in 1 unit cell is `6/8`. Since 3 face-centered atoms (B) contribute to one unit cell, the formula is
A6/8B3 or A6B24 or AB4