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The binding energy of an electron in the ground state of the He atom is equal to 24 eV. The energy required to remove both the electrons from the atom will be :–
A. |
59 eV |
B. |
81 eV |
C. |
79 eV |
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D. |
None of these |
Ionization energy of He=`z^2/n^2xx13.6=2^2/1^2xx13.6=54.4 eV`
Energy required to remove the electrons
= Binding energy + Ionization energy = 24.6 + 54.4 = 79 eV