Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) If the normal at any point P of the ellipse `X^2/16+Y^2/9=1` meets the corrdinates axes at M and N, respectively, then |PM||PN| equals – - Sarthaks eConnect

If the normal at any point P of the ellipse `X^2/16+Y^2/9=1` meets the corrdinates axes at M and N, respectively, then |PM|:|PN| equals :–

If the normal at any point P of the ellipse `X^2/16+Y^2/9=1` meets the corrdinates axes at M and N, respectively, then |PM|:|PN| equals :–

A.

4 : 3

B.

16 : 9

C.

9 : 16

D.

3 : 4

Solution

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Best answer

The equation of the normal at P`(theta)` on the ellipse is 4x sec `theta` – 3y cosec `theta` = 7 This meets the coordinate axes at