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If `lim_(x->a)[f(x) g(x)] =2` and `lim_(x->a)[f(x) g(x)]` , then `lim_(x->a)f(x)g(x)`
A. |
Need not exist |
B. |
exists and is `3/4` |
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C. |
exists and is `-3/4` |
D. |
exists and is `4/3` |