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Arrange following in correct sequence of basic strength
A. |
IV > I > III > II |
B. |
III > I > II > IV |
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C. |
II > I > III > IV |
D. |
I > III > II > IV |
More free the electron present on N atom as a lone pair, more will be its basic strength. In IV lone pair of nitrogen is involved in acromatic `6pi` electrons, hence IV is least basic among all.