Failed to connect to MySQL: Access denied for user 'examnext_online'@'localhost' (using password: YES) Arrhenius proposed a quantitative relationship between rate constant and temperature as k = `Ae^-((Ea) /(RT))` or ln k = `ln A – E_a/(RT)`. What will be the slope of graph when ln k is plotted versus` 1/T `? - Sarthaks eConnect

Arrhenius proposed a quantitative relationship between rate constant and temperature as k = `Ae^-((Ea) /(RT))` or ln k = `ln A – E_a/(RT)`. What will be the slope of graph when ln k is plotted versus` 1/T `?

Arrhenius proposed a quantitative relationship between rate constant and temperature as k = `Ae^-((Ea) /(RT))` or ln k = `ln A – E_a/(RT)`. What will be the slope of graph when ln k is plotted versus` 1/T `?

A.

`E_a/R`

B.

`-E_a/R`

C.

`1/T`

D.

ln A

Solution

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Best answer

According to Arrhenius equation, we know that